Write $47$ in binary form.

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Solution

Step 1: To write $47$ in binary form, we will divide $47$ by $2$ repeatedly until the quotient becomes zero.
Dividend Remainder
$47 \div 2 = 23$ $1$
$23 \div 2 = 11$ $1$
$11 \div 2 = 5$ $1$
$5 \div 2 = 2$ $1$
$2 \div 2 = 1$ $0$
$1 \div 2 = 0$ $1$
Step 2:
Now, we will write the remainder from bottom to top.
This will give the required binary form of $47 = 101111$
Hence, the required binary form of $47$ is $101111$ .

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