Solution of correct option ( 5/7)^ 5=__By the law of exponent: a^ n=1/a^n[ ∴( 5/7)^ 5 = 1/( 5/7)^5; = ( 7/5)^5 ]Hence ( 5/7)^ 5= ...

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Standard VIII

Mathematics

Powers with Negative Exponents

-5/7-5=

Question

${(\frac{- 5}{7})}^{- 5} =__$

${(\frac{5}{7})}^{- 5}$

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${(\frac{5}{7})}^{5}$

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${(\frac{7}{5})}^{5}$

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${(\frac{- 7}{5})}^{5}$

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Solution

The correct option is D
${(\frac{- 7}{5})}^{5}$

Solution of correct option-
${(\frac{- 5}{7})}^{- 5} =__$
By the law of exponent: $a^{- n} = \frac{1}{a^{n}}$
$\begin{array}{rcl} ∴ {(\frac{- 5}{7})}^{- 5} & = & \frac{1}{{(\frac{- 5}{7})}^{5}} \\ = & {(\frac{- 7}{5})}^{5} \end{array}$
Hence- ${(\frac{- 5}{7})}^{- 5} = {(\frac{- 7}{5})}^{5}$

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-57-5=__

The correct option is D -755Solution of correct option--57-5=__By the law of exponent: a-n=1an∴-57-5=1(-57)5=-755Hence- -57-5=-755

${(\frac{- 5}{7})}^{- 5} =__$