Question

$\sqrt{6}$ multiply with $\sqrt{27}$ is equal to

Answer 1

We have- $\sqrt{6}\times \sqrt{27}$

$$\begin{gathered} =\sqrt{6\times 27} \\ =\sqrt{162} \\ =\sqrt{2\times 3\times 3\times 3\times 3}\left(\mathrm{By}\mathrm{prime}\mathrm{factorisation}\right) \\ =9\sqrt{2} \end{gathered}$$

Hence, $\sqrt{6}\times \sqrt{27}$$=9\sqrt{2}$