Factorise by splitting the middle term.
$7 x^{2} - 25 x + 12 .$

Open in App

Solution

Split the middle term
$7 x^{2} - 25 x + 12 .$
$= 7 x^{2} - 21 x - 4 x + 12$ (Split the middle term in such a way that the Sum of the split terms should be equal to the middle terms $- 21 x + (- 4 x) = - 25 x$ ) and its product should be equal to the product of the coefficient of $x^{2}$ and constant term $7 \times 12 = - 21 \times - 4 = 84$ )
$= 7 x (x - 3) - 4 (x - 3)$ ( Take $7 x$ common from $7 x^{2}$ and $- 21 x$ and $- 4$ from $- 4 x$ and $12$ )
$= (7 x - 4) (x - 3)$ ( Write common factor once and other factors together )
Hence, the factors of $7 x^{2} - 25 x + 12$ are $(7 x - 4)$ and $(x - 3)$ .

Suggest Corrections

Similar questions

Factorise :7 – 12𝑥 − 4𝑥^2 by splitting the middle term

12 x^{2} - 7 x + 1

Factorise by splitting the middle term: 24x²- 65x + 21

3 x^{2} + 7 x + 2

9 (x - 2 y)^{2} - 4 (x - 2 y) - 13

Join BYJU'S Learning Program