wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 24kg block resting on a floor has a rope tied to its top. The maximum tension the rope can withstand without breaking is 310N. The minimum time in which the block can be lifted a vertical distance of 4.6m by pulling on the rope is


A

1.2s

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

1.3s

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

1.7s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

2.3s

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

1.7s


Step 1: Given Data

Mass of the block m=24kg

Maximum tension on the rope T=310N

Height at which the block is to be lifted h=4.6m

Let the acceleration in the upward direction be a.

Let the acceleration due to gravity be g=10m/s2.

Step 2: Calculate the Acceleration

The tension acts in the upward direction and the weight of the block acts in the downward direction.

Therefore, the equation of motion can be written as,

T-mg=ma

T=mg+a

Upon substituting the values we get,

310=2410+a

a=31024-10

a=3512m/s2

Step 3: Calculate the time taken

According to Newton's second equation of motion,

S=ut+12at2

Since the initial velocity is zero, the equation can be rewritten as,

h=12at2

t=2ha

Upon substituting the values we get,

t=2×4.6×1235=1.7s

Hence, the correct answer is option (C).


flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon