A, B and C can solve 50%, 60% and 70% of the sums from a book. If one sum from that book is given them to solve then probability that the sum will be solved is _____

P(A) = (50 / 100) = (5 / 10)

P(B) = (60 / 100) = (6 / 10) and 

P(C) = (70 / 100) = (7/10) 

A, B, C are independent events. 

∴ P (A ∪ B ∪ C)  = 1 – P(A ∪ B ∪ C)’ 

= 1 – P(A’) ∙ P(B’) ∙ P(C’) 

= 1 – [(5 / 10) (4 / 10) (3 / 10)] 

= 1 – (6 / 100) 

= 0.94

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