Question

A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of $12m{s}^{-1}$. If the mass of the ball is $0.15kg$, the impulse imparted to the ball is

• A. $3.6Ns$
• B. $2.8Ns$
• C. $4.2Ns$
• D. $3.9Ns$

Answer 1

The correct option is A

$3.6Ns$

Step 1: Given Data

The first velocity $v_1=12m/s$

Since only the direction of the ball changes the second velocity $v_2=-12m/s$

Mass of the ball $m=0.15kg$

Step 2: Formula Used

We know that momentum is given as

$p=mv$

We know that impulse is given as

$I=∆p$

$\Rightarrow I=m{v}_1-m{v}_2$

$\Rightarrow I=m\left(v_1-v_2\right)$

Step 3: Calculate the Impulse

Upon substituting the values we get,

$I=0.15\left\{12-\left(-12\right)\right\}$

$=0.15kg\times 24m/s$

$=3.6Ns$

Hence, the correct answer is option (A).