A battery of emf 10 v and internal resistance 3 omega is connected to a resistor. The current in the circuit is 0.5A. The terminal voltage of the battery when the circuit is closed is?

Given,

EMF of battery=10v

Internal rssitance of battery, r=3 ohms

Current in the circuit, I=0.5A

Resistanc of the resistor=R

By Ohm’s law, we know;

I = E/(R+r)

So, R=17 ohms

The terminal voltage of the resistor=V

Ohm’s law states:

V=IxR

So, V= 8.5V

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