A Beaker Containing Water Is Placed On The Platform Of A Spring Balance. The Balance Reads 1.5 Kg. A Stone Of Mass 0.5 Kg And Density 104 Kg/M3 Is Immersed In Water Without Touching The Walls Of The Beaker. What Will Be The Balance Reading Now?

Sol:

Since the weight of the block must be equal to the buoyant force acting on the block for it to remain in equilibrium,

B = 0.5kg

The reading of the spring balance = Weight of water + Buoyant force reaction pair force downwards

= 1.5 kg + 0.5 kg = 2 kg

Therefore, the balance reading will be 2 kg.

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