A Beaker Containing Water Is Placed On The Platform Of A Spring Balance. The Balance Reads 1.5 Kg. A Stone Of Mass 0.5 Kg And Density 104 Kg/M3 Is Immersed In Water Without Touching The Walls Of The Beaker. What Will Be The Balance Reading Now?


Since the weight of the block must be equal to the buoyant force acting on the block for it to remain in equilibrium,

B = 0.5kg

The reading of the spring balance = Weight of water + Buoyant force reaction pair force downwards

= 1.5 kg + 0.5 kg = 2 kg

Therefore, the balance reading will be 2 kg.

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