Question

A body has an initial velocity of 4 m/s and deceleration of 4 m/s2, then what is its final velocity after traveling 2m?

Answer 1

Step1: Given data

Initial velocity, $u=4m/s$

Deceleration, $a=-4m/s^2$

Distance, $s=2m$

Step2: Formula used

The third equation of motion says,

$v^2=u^2+2as[wherev=finalvelocity,u=initialvelocity,a=acceleartion,s=displacement]$

Step3: Calculating the final velocity

$$\begin{gathered} v^2=u^2+2as \\ {v}^2={\left(4\right)}^2+2(-4)\left(2\right) \\ {v}^2=16-16 \\ {v}^2=0 \\ v=0 \end{gathered}$$

Hence, the final velocity after travelling 2m will be 0.