A car moving along a straight highway with speed of 126 km/h is brought to a stop within a distance of 200 m. What is the retardation of the car and how long does it take for the car to stop?

Given:

u = 126 km/h = 126×5/18 m/s = 35 m/s

v = 0

s = 200 m

Using Newton’s equation of motion,

v<sup>2</sup>-u<sup>2</sup>=2as

0<sup>2</sup>-35<sup>2</sup>=2a(200)

a=-3.065 m/s<sup>2</sup>

Now,

v=u+at

0=35-3.06t

t=11.4s

Was this answer helpful?

 
   

0 (0)

(0)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question