Question

A car weighing $100kg$ is on a slope that makes an angle $30°$ with the horizontal. The component of car’s weight parallel to the slope is ($g=10m/s^2$)

• A. $500N$
• B. $1000N$
• C. $15000N$
• D. $20000N$

Answer 1

The correct option is A

$500N$

Step 1: Given

Weight of the car, $W=100Kg$

Angle, $\theta =30°$

Acceleration due to gravity, $g=10m/s^2$

Step 2: Draw the free body diagram

The weight of the car can be resolved into two components: horizontal and vertical.

Step 3: Determine the weight

The question asks for the parallel weight component of the car.

$$\begin{gathered} W\text{'}=W\sin 30° \\ =mg\sin 30° \\ =\left(100Kg\right)(10m/s^2)(0.5) \\ =500N \end{gathered}$$

Therefore, option A is the correct option.