Question

A chord of a circle of radius$10cm$ subtends a right angle at the centre. Find the area of the corresponding:

Minor segment (Use $\pi =3.14$)

Answer 1

Given

A chord of a circle of radius$10cm$subtends a right angle at the centre.

Area of minor segment =Area of sector – Area of the triangle

$$\begin{gathered} =\frac{\theta }{360°}\times \pi r^2-\frac{1}{2}\times b\times h \\ =\frac{90}{360}\times 3.14\times 10\times 10-\frac{1}{2}\times 10\times 10 \\ =\frac{314}{4}-50 \\ =78.5-50 \\ =28.5c{m}^2 \end{gathered}$$

Hence, area is $28.5c{m}^2$ .