Given
A chord of a circle of radius 10 cm subtends a right angle at the centre.
Find out
We have to find out the area of the corresponding:
(i) minor segment
(ii) major sector. (Use π = 3.14)
Solution
Radius =r=10cm
The major segment is =360°-90°=270°
(i) Area of minor segment =Area of sector – Area of the triangle
=∅/(360°) *πr2-1/2*h*b
=90/306*3.14*10*10-1/2*10*10
=314/4-50
=78.5-50
= 28.5 cm2
(ii)Area of major sector=∅/(360°) *πr2
=270/360*3.14*10*10
=3*314/4=235.5cm2
Area of major segment=235.5cm2