Question

A coin is tossed three times. The number of possible outcomes is

• A. $3$
• B. $4$
• C. $6$
• D. $8$

Answer 1

The correct option is D

$8$

When a coin is tossed once, the number of outcomes is two (Head and Tail) i.e., in each throw, the number of ways of showing a different face is $2$.Similarly tossing the coin for the second time, there are again the same two outcomes and similarly, for a third toss, the same outcomes appear.
Thus, by the multiplication principle, the required number of possible outcomes is $2\times 2\times 2=8$.

So, the outcomes are $HHH,THH,HTH,HHT,TTH,THT,HTT,TTT$.