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Question

A compound XY crystallizes in BCC lattice with a unit cell edge length of 480 pm. If the radius of Y is 225 pm. What will be the radius of X+


A

225pm

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B

255pm

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C

127.5pm

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D

190.68pm

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Solution

The correct option is D

190.68pm


The explanation for the correct answer:-

Option (D) 190.68 pm

Step 1: Given data

As we know, the sum of the ionic radii is the nearest neighbour distance ‘d’.

In the case of a body-centred cubic unit cell, where a is the unit cell length.

Unit cell edge length of 480 pm

Radius of Yis225pm

Step 2: Formula used

Neighbour distance, d=32a

Step 3: Calculating neighbour distance

From 1) we get, d = 415.68pm.

Step 4: Deriving radius of X+

As X++Y- = 415.68 pm

Therefore, X+ = 415.68225.00

=190.68pm.

Hence, the radius of X+ is 190.68pm, option (D) is the correct answer.


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