The water film has two surfaces therefore increase in area\( \Delta S = 2 * 10 * 0.1 = 2cm^{2} \)

The work required to be done\( W = \Delta S * T \)

=\( 2 * 12 * 10^{-4} * 72 * 10^{-3} \)

= \( 144 * 10^{-7} * 72 * 10^{-3} \)

=\( 144 * 10^{-7} \)

= \( 1.44 * 10^{-5}joule \)

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