Question

A flooring tile has the shape of a parallelogram whose base is $24cm$ and the corresponding height is $10cm$. How many such tiles are required to cover a floor of

area $1080m^2$?

[If required you can split the tiles in whatever way you want to fill up the corners]

Answer 1

Step 1: Let's find the area of the flooring tile.

Here, base of flooring tile $24cm=0.24m$

Corresponding height of a flooring tile $=10cm=0.10m$

Area of flooring tile $=Base\times Altitude=0.24\times 0.10=0.024$

The area of flooring tile is $0.024m^2$

Step 2: Let's find the number of tiles that are required to cover the floor.

Number of tiles required to cover the floor $=\frac{Areaoffloor}{Areaofonetile}=\frac{1080}{0.024}=45000tiles$

Hence, $45000$ tiles are required to cover the floor.