Sol:

Given:

Diameter = 36 cm

Number of bottles – 72

Diameter = 6 cm

If the Diameter = 6 cm, then the radius will be 18 cm.

Volume of hemispherical bowl = \(frac{2}{3}\) πr3

= \(frac{2}{3} * frac{22}{7} \) * (18)3

= 12219.43 cm3

Given radius of cylinder = 3 cm

The volume of cylinder = πr3 h

The volume of 72 bottles =

= \(frac{22}{7}\) * (3)2 * h * 72

If 10% liquid is wasted in this transfer, then.

10% of 12219.943 is 1221.943

The remaining volume of liquid is 12219.943 − 1221.943 = 10997.487 cm3

Therefore,

= 72 * \(frac{22}{7}\) * 3 * 3 * h

= h = \(frac{10997.487 * 7}{72 * 22 * 9}\)

= h = 5.4 cm

Therefore, the height (h) of each bottle is 5.4 cm.

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