A particle has initial velocity (2i+3j) and acceleration (0.3i+0.2j) the magnitude of the velocity after 10 second will be: (a) 9√2 units (b) 5√2 units (c) 5 units (d) 9 units

Answer: (b)5√2

Given,

u = 2i + 3j

a = 0.3i + 0.2j

t = 10s

As, v = u + at

v = (2i + 3j) + (0.3i + 0.2j) (10)

= 2i + 3j + 3i + 2j

= 5i + 5j |v|

= √(52 + 52)

= 5√2

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