A Projectile Can Have The Same Range R For Two Angles Of Projection. If T1 & T2 Be The Times Of Flight In The Two Cases Then What Is The Product Of Two Times Of Flight?

As given in the question Range is same for two angles of projection

\( \Theta and (90 – \Theta) \) \( t_{1} = 2u sin\Theta /g \) \( t_{2} = [2u sin(90 – \Theta)] /g \)

=\( 2u cos\Theta /g \)

Therefore,

\( t_{1}t_{2} = 4(u^{2} sin\Theta cos\Theta /g^{2}) \)

=\( 2/g[u^{2}sin\Theta/g] \)

=\( (2/g)R, \)

Where R is the range

Hence,\( t_{1}t_{2} \propto R. \) As R is constant

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