Question

A racing car has a uniform acceleration of $4{\mathrm{ms}}^{-2}$. What distance will it cover in $10\mathrm{s}$ after start?

Answer 1

Step 1: Given

Final acceleration, $a=4{\mathrm{ms}}^{-2}$

Time period, $t=10\mathrm{s}$

The car has uniform acceleration. This means that initially, it was in rest. Thus,

Initial velocity, $u=0{\mathrm{ms}}^{-1}$

Step 2: Formula used

As per the second equation of motion,

$s=ut+\frac{1}{2}a{t}^2$, where $s$ is the distance covered.

Step 3: Calculate the distance covered

Substituting the values in the above equation,

$\begin{array}{rcl}s& =& 0\times 10+\frac{1}{2}\times 4\times {10}^2\\ \therefore s& =& 200\mathrm{m}\end{array}$

Therefore, the car will cover a distance of $200\mathrm{m}$ in $10\mathrm{s}$ after start.