A ray of light undergoes refraction and looses 0.25 times of its velocity.If 'i' is the angle of incidence and is very small,the angle of deviation for the ray of light is______

Given that

A ray of light undergoes refraction and looses 0.25 times of its velocity.

Angle of incidence is i

We need to find the angle of deviation for the ray of light

Hence, As per the law of refraction, we know that

μ1 sin i =μ2 sin r ————-(1)

We also know that

μ1/ μ2 = ν1 / v2 ——————(2)

As per given condition A ray of light undergoes refraction and looses 0.25 times of its velocity.

Hence 1-o.2=0.75

= v2 = 0.75 ν1

Now we can equate this to equation (2)

μ1/ μ2 = 0.75

now for small angle we know the formula

r = μ1/ μ2i

r = 0.75 i

so angle of deviation is given as

δ = i – r

δ = 0.25 i

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