# A rectangular sheet of paper is $$12\frac{1}{2}$$ cm long and $$10\frac{2}{3}$$ cm wide. Find its perimeter.

Solution:-

From the given details, we get to know that

Length = $$12\frac{1}{2}$$ cm = 25/2 cm

Breadth =$$10\frac{2}{3}$$ = 32/3 cm

We know that,

Perimeter of the rectangle = 2 × (length + breadth)

= 2 × [(25/2) + (32/3)]

= 2 × {[(25 × 3) + (32 × 2)]/6}

= 2 × [(75 + 64)/6]

= 2 × [139/6]

= 139/3 cm

On converting 139/3 into mixed fraction we get

=$$46\frac{1}{3}$$

Hence, the perimeter of the sheet of paper is=$$46\frac{1}{3}$$