A rectangular sheet of paper is \(12\frac{1}{2}\) cm long and \(10\frac{2}{3}\) cm wide. Find its perimeter.

Solution:-

From the given details, we get to know that

Length = \(12\frac{1}{2}\) cm = 25/2 cm

Breadth =\(10\frac{2}{3}\) = 32/3 cm

We know that,

Perimeter of the rectangle = 2 × (length + breadth)

= 2 × [(25/2) + (32/3)]

= 2 × {[(25 × 3) + (32 × 2)]/6}

= 2 × [(75 + 64)/6]

= 2 × [139/6]

= 139/3 cm

On converting 139/3 into mixed fraction we get

=\(46\frac{1}{3}\)

Answer

Hence, the perimeter of the sheet of paper is=\(46\frac{1}{3}\)

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