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Question

A solution containing active cobalt 2760 co having activity of 0.8μciand decay constant λ is injected into an animal's body. If 1cm3 of blood is drawn from the animal's body after 10hrs of injection, the activity found was 300 decays per minute. What is the volume of blood that is flowing in the body?

(1Ci=3.7×1010FcayPerSecondandAtT=10HrsE-λT=0.84)


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Solution

The activity equation can be written as

dNdt=λNoeλt

Substituting the values, we get:

λNo=0.8μCi

Substituting the values, we get:

λNo=2.96104

Let the volume of the blood flowing be V

The activity would reduce by a factor of

103V

Therefore,

λNo103Veλt=300/60.

Now substituting the values of

eλtandλNo,

we get,

V=5litre


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