Height of the object, $$h_{0} = 3 cm$$

Width of the object, $$b_{0} = 3 cm$$

Width of the object

Now using mirror formula =$$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$$

Given values, u = -25cm and f = -10 cm

$$\Rightarrow \frac{1}{v} + \frac{1}{-25} = \frac{1}{-10}$$ $$\Rightarrow v = \frac{-25}{15} cm$$

Magnification = $$\frac{h_{i}}{h_{0}} = \frac{-v}{u}$$

Therefore, $$\frac{h_{i}}{3} = \frac{-v}{u}$$ $$\Rightarrow \frac{-25/15}{25}$$ $$\Rightarrow h_{i} = 2 cm$$ $$\Rightarrow h_{i} = 2 cm$$

The area of image formed $$A_{i} = h_{i}b_{i}$$ $$\Rightarrow 2 * 2 = 4$$

Thus the area of the image formed = $$4 cm^{2}$$

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