Height of the object, \( h_{0} = 3 cm\)

Width of the object, \( b_{0} = 3 cm \)

Width of the object

Now using mirror formula =\( \frac{1}{v} + \frac{1}{u} = \frac{1}{f}\)

Given values, u = -25cm and f = -10 cm

\(\Rightarrow \frac{1}{v} + \frac{1}{-25} = \frac{1}{-10}\) \(\Rightarrow v = \frac{-25}{15} cm\)

Magnification = \( \frac{h_{i}}{h_{0}} = \frac{-v}{u}\)

Therefore, \(\frac{h_{i}}{3} = \frac{-v}{u}\) \(\Rightarrow \frac{-25/15}{25}\) \(\Rightarrow h_{i} = 2 cm\) \(\Rightarrow h_{i} = 2 cm\)

The area of image formed \( A_{i} = h_{i}b_{i}\) \( \Rightarrow 2 * 2 = 4\)

Thus the area of the image formed = \( 4 cm^{2}\)

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