A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.

Given that

Initial velocity

u = 0

Tower height = total distance = 19.6m

g = 9.8 m/s2

Find out

Final velocity just before touching the ground.

Solution

Let us solve using third equation of motion

v2 = u2 + 2gs

v= 0 + 2 × 9.8 × 19.6

v2 = 384.16

v = √(384.16)

v = 19.6m/s

Answer

Final velocity just before touching the ground = v = 19.6m/s

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