A submarine emits a sonar pulse, which returns from an underwater cliff in $1.02 s$ . If the speed of sound in salt water is $1531 m s^{- 1}$ , how far away is the cliff?

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Solution

Step 1: Given
Time taken by sonar pulse to return, $t = 1.02 s$
Time taken by sonar pulse to hit the cliff, $t' = \frac{t}{2} = 0.51 s$
Speed of sound in salt water = $1531 m s^{- 1}$
Step 2: Formula used and calculation
Distance of the cliff from the submarine $= s p e e d \times t i m e = 1531 \times 0.51 = 780.51 m$
The cliff is $780.51 m$ far from the submarine.

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A submarine emits a sonar pulse, which returns from an underwater cliff in 1.02s. If the speed of sound in salt water is 1531ms-1, how far away is the cliff?

A submarine emits a sonar pulse, which returns from an underwater cliff in $1.02 s$ . If the speed of sound in salt water is $1531 m s^{- 1}$ , how far away is the cliff?