A truck of mass M is moved under a force F. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved, then how does the acceleration change?

Answer:

Force = mass x acceleration

F = m × a

a1 = F/m

When mass is doubled force is halved then

m = 2m

F = F/2

a2 = F/4m

a1/a2 = (F/m)/(F/4m)

a1/a2 = F/m × 4m/F

a1/a2 = 1/4

acceleration reduces to 1/4th

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