Depth (h1) of well = 14 m
Radius (r1) of the circular end of well = 3/2m

Width of embankment = 4 m
From the figure, it can be observed that our embankment will be in a cylindrical shape having outer radius, (r2)= 4+3/2 = 11/2m

Let height of embankment be h2.
Volume of soil dug from well = Volume of earth used to form the embankment
π×r12×h1=π×(r22−r12)×h2
π × (3/2)2 ×14=π×[11/2]2 – (3/2)2 ×h2
h2 = 9/8 = 1.125m
So, the height of the embankment will be 1.125 m.

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