A Wire Suspended Vertically From One of Its Ends Is Stretched by Attaching a Weight of 200N to the Lower End. The Weight Stretches the Wire by 1mm. Then the Elastic Energy Stored in the Wire Is

A wire suspended vertically from one of its ends is stretched by attaching a weight of 200N to the lower end. The weight stretches the wire by 1mm. Then the elastic energy stored in the wire is 0.1 J.


Elastic energy = (1/2) F × x

Here, F = 200N and x = 1mm = 1 × 10-3

E = (1/2)×200×10-3

E = 0.1 J.

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