ABC and DBC are two isosceles triangles on the same base BC (see Fig.) . Show that ABD = ACD.

Solution

Given

 AB=AC,BD=DC

To Prove

 ∠ABD = ∠ACD

Proof

From ∆ABD,

AD=AC

∴∠1=∠2 [angle opposite to equal sides are equal] [1]

In ∆BDC,

BD=DC

∴∠3=∠4 [angle opposite to equal sides are equal] [2]

Adding 1 and 2

∠1+∠2= ∠2+∠4

∠ABD=∠ACD

Hence Proved

Was this answer helpful?

  
   

0 (0)

Upvote (0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question