ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively (see Fig.) . Show that these altitudes are equal.

Solution

Given

AB=AC,

BE and CF are altitudes 

To Prove

BE=CF

Proof

From ∆AEB and ∆AFC,

∠E=∠F

∠A=∠A

AB=AC

∴∆AEB≅∆AFC [A.A.S congruency]

BE=CF

Was this answer helpful?

 
   

4 (12)

(18)
(2)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published.

*

*

close
close

DOWNLOAD

App Now

Ask
Question