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Question

ABCD is a rhombus such that ACB=40° Then ADB is


A

40º

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B

45º

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C

50º

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D

60º

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Solution

The correct option is C

50º


The explanation for the correct option:

Option (C):50°

Solution:

According to the given details, ABCD is a rhombus

ACB=40°

ACB=40°OCB=40°

ADBC (opposite sides of the rhombus are parallel)

DAC=BCA=40° [Alternate interior angles]

DAO=40°

We know that the diagonals of a rhombus are perpendicular to each other

So,

AOD=90°

We also know that the sum of interior angles of a triangle is 180°.

Sum of all angles of a triangle =180°

AOD+ADO+DAO=180°90°+ADO+40°=180°130°+ADO=180°ADO=180°130°ADO=50°ADB=50°

Hence,ADB=50°


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