Add the following: a-b+ab,b-c+bc,c-a+ac
To add : a-b+ab,b-c+bc,c-a+ac
On combining the like terms and adding them we get
=(a–b+ab)+(b–c+bc)+(c–a+ac)=a–b+ab+b–c+bc+c–a+ac=a–a+b–b+c–c+ab+bc+ca=0+0+0+ab+bc+ca=ab+bc+ca
Hence, On adding a-b+ab,b-c+bc,c-a+ac we get ab+bc+ca.
Question 10
In ΔABC,
a) AB + BC > AC b) AB + BC < AC c) AB + AC < BC d) AC + BC < AB
Add following.(i) ab−bc,bc−ca,ca−ab(ii) a−b+ab,b−c+bc,c−a+ac(iii) 2p2q2−3pq+4,5+7pq−3p2q2(iv) l2+m2,m2+n2,n2+l2,2lm+2mn+2nl