Add the following: a - b + ab, b - c + bc, c - a + ac

Answer: ab + bc + ca

(a – b + ab) + (b – c + bc) + (c – a + ac)

(a – b + ab) + (b – c + bc) + (c – a + ac) = a – b + ab + b – c + bc + c – a + ac

(a – b + ab) + (b – c + bc) + (c – a + ac) = a – a +b – b + c – c + ab + bc + ca

(a – b + ab) + (b – c + bc) + (c – a + ac) = 0 + 0 + 0 + ab + bc + ca

(a – b + ab) + (b – c + bc) + (c – a + ac) = ab + bc + ca

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