Aluminium crystallises in an FCC structure. Atomic radius of the metal is 125 pm. What is the length of the side of the unit cell of the metal?

For cubic close packed structure, let a is the edge and r is the radius of the atom

Given that r = 125 pm

Length of the side of the unit cell in FCC structure, a = (4/√2)r 

a = 2√2r

We know the value of √2 = 1.414

On substituting, we get,

a = 2 x 1.414 x 125

We get,

a = 353.5 pm

Hence, the edge length of the face centered cubic structure of aluminium is 353.5 pm

Was this answer helpful?


0 (0)


Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *




Free Class