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Question

Among the following the molecule expected to be stabilized by anion formation is C2,O2,NO,F2?


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Solution

The stabilization by anion formation can be seen by calculating the bond order which tells whether the incoming electron will enter the bonding or the anti-bonding orbital.

1.C2

  • The number of valence electrons in C2are 12.
  • The electronic configuration C2:(σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(Ï€2px2=Ï€2py2)
  • Bondorder=(numberofelectronsinbondingMOT–numberofelectronsinantibondingMOT)2Bondorder=8-42=42Bondorder=2
  • In C2 the incoming electron will enter the bonding molecular orbital which increases the bond order and stability.

2. O2

  • The number of valence electrons in O2are 16.
  • The electronic configuration of O2: (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(Ï€2px2=Ï€2py2)(Ï€*2px1=Ï€*2py1)
  • Bondorder=(numberofelectronsinbondingMOT–numberofelectronsinantibondingMOT)2Bondorder=10-62=42Bondorder=2
  • In O2 the incoming electron will enter the anti-bonding molecular orbital which decreases the bond order and stability

3. NO

  • The number of valence electrons in NO are 15.
  • The electronic configuration of NO: (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(Ï€2px2=Ï€2py2)(Ï€*2px1)
  • Bondorder=(numberofelectronsinbondingMOT–numberofelectronsinantibondingMOT)2Bondorder=10-52=52Bondorder=2.5
  • In NO the incoming electron will enter the anti bonding molecular orbital which decreases the bond order and stability

4. F2

  • The number of valence electrons in F2 are 14.
  • The electronic configuration of F2 : (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2pz)2(Ï€2px2=Ï€2py2)(Ï€*2px2=Ï€*2py2)
  • Bondorder=(numberofelectronsinbondingMOT–numberofelectronsinantibondingMOT)2Bondorder=10-82=22Bondorder=1
  • In F2 the incoming electron will enter the anti-bonding molecular orbital which decreases the bond order and stability.

Thus, In C2 the incoming electron will enter the bonding molecular orbital which increases the bond order and stability while in other molecules it will enter the bonding orbital.


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