Question

An electric kettle consumes $1kW$ of electric power when operated at $220V$. A fuse wire of what rating must be used for it?

Answer 1

Step1: Given data

1. The power of the electric kettle is, $P=1000watt.$
2. supplied voltage, $V=220volt.$

Step2: Electric fuse

1. A fuse is a safety device that prevents any type of short circuit due to high voltage and high electric flow through a circuit.
2. A fuse is a thin wire of high resistance and low melting point. The fuse is designed in such a way that it will protect our domestic electric appliances from any kind of short circuit.

Step3: Fuse rating and power

1. A fuse can give a maximum current that an electrical appliance requires, this maximum amount of current is called the rating of a fuse.
2. Now we know now, the power of a circuit is, $P=VI$, where, V is the supplied voltage and I is the current through the circuit.

Step4: Calculation of current

As we know, $P=VI$

So, the maximum current passes through the circuit is,

$$\begin{gathered} I=\frac{P}{V}=\frac{1000}{220}=4.54 \\ or4.54A. \end{gathered}$$

Therefore, a fuse of rating $4.54A$ or above has to be used.