Question

An iceberg of density ${\rho }_{ice}=900\frac{\text{kg}}{{\text{m}}^3}$ Is Floating In Water Of Density ${\rho }_{water}=1000\frac{\text{kg}}{{\text{m}}^3}$. What Will Be The Percentage Of Volume Of Ice-cube Outside The Water?

Answer 1

Step 1:Given:

${\rho }_{ice}=900\frac{\text{kg}}{{\text{m}}^3}$

${\rho }_{water}=1000\frac{\text{kg}}{{\text{m}}^3}$

Step 2:Calculate Percentage Of Volume Of Ice-cube Outside The Water.

$$\begin{gathered} V_{outside}=\left(1-\frac{{\rho }_{ice}}{{\rho }_{water}}\right)\times 100 \\ =\left(1-\frac{900}{1000}\right)\times 100 \\ =10\% \end{gathered}$$

Hence, the percentage of volume of Ice-cube outside the water is $10\%$.