According to the equation of continuity

$$A_{1}v_{1} = A_{2}v_{2}$$ $$\frac{v_{1}}{v_{2}} = \frac{A_{1}}{A_{2}}$$

=$$\frac{\pi D_{2}^{2}/4}{\pi D_{1}^{2}/4}$$

=$$\left (\frac{D_{2}}{D_{1}} \right)^{2}$$

Given,diameters 2.5cm and 3.75cm D

$$D{1} = 2.5cm and D_{2} = 3.75cm$$

Now by substituting the values:

=$$\left (\frac{D_{2}}{D_{1}} \right)^{2}$$

=$$\left (\frac{3.75}{2.5}\right)^{2}$$

=$$\left (\frac{3}{2}\right)^{2}$$

=$$\frac{9}{4}$$

Therefore, the ratio of the velocities in the two pipes is 9:4

Explore more such questions and answers at BYJU’S.

Was this answer helpful?

0 (0)

Upvote (0)

#### Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.