An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.

Given

The length of two equal sides of an isosceles triangle is 12 cm.

Perimeter = 30 cm.

Find out

We have to determine the area of a triangle

Formula

By using Heron’s formula, area of triangle= \(\sqrt{s(s-a)(s-b)(s-c)}\)

Solution

The length of third side = (Perimeter)-(length of two side)

= 30-(12+12)

= 6 cm

a = 12 cm

b = 12 cm

c = 6 cm

Semi Perimeter (s) = (a+b+c)/2

s = (12+12+6)/2

s = 15 cm

ar(△ABC) = √s(s-a)(s-b)(s-c)

= √15(15-12)(15-12)(15-6)

= √15×(3)×(3)×(9)

= 9√15 cm2

Answer

Hence, the area of triangle is 9√15 cm2

Was this answer helpful?

  
   

0 (0)

Upvote (0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question