Area of a rectangle with length $4 a b$ and breadth $6 b^{2}$ is

$24 a^{2} b^{2}$

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$24 a b^{3}$

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$24 a b^{2}$

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$24 a b$

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Solution

The correct option is B
$24 a b^{3}$

Given
$L e n g t h = 4 a b, B r e a d t h = 6 b^{2}$
We know that,
Area of rectangle $= l e n g t h \times b r e a d t h$
$= 4 a b \times 6 b^{2} = 24 a b^{3}$
Thus, the area of the rectangle is $24 a b^{3}$
Hence, the correct option is (b).

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