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Question

As the result of a wind blowing normal to the plane of the rectangular sign, a uniform pressure of 175N/m2 is exerted in the direction shown in the figure. Determine the moment of the resulting force at about point 0. Express your result as a vector using the coordinates shown.


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Solution

Step 1: Given information

Uniform pressure, p=175N/m2

Width is 600mm.

Height is 750mm.

Step 2: To find

We have to determine the result as a vector using the coordinates shown.

Step 3: Calculate

The net force will be:

F=pa

F is the force.

p is the pressure.

a is the acceleration.

By substituting the values, we get

=175×(600×750)×10-6=78.75N

By using the figure,

The direction of force be 78.75(-i^)

Now,

r^=100+7502

1.375m(j^)

τ=r×F

By substituting the values,

=1.375(j^)×78.75(-i^)=108.28k^

Therefore, the result as a vector will be 108.28k^.


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