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Question

At very high pressures the compressibility factor of one mole of a gas is given by:


A

1+pbRT

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B

1-pbRT

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C

1-bVRT

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D

pbRT

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Solution

The correct option is A

1+pbRT


Explanation for correct option:

(A) 1+pbRT

  • Compressibility Factor is also often defined as “the ratio of molar volume of gas to that of an ideal gas.”

Step 1: Vanderwaals equation

  • The van der Waals equation for 1 mole of gas is :
    p+aV2(Vb)=RTp-pressureV-volumeT-temperatureR-Universalgasconstant

Step 2: High pressure neglection factor

  • At very high pressure, the ratio aV2 can be neglected in comparison to p, and the equation becomes :
    p(Vb)=RTpV-pb=RTpV=RT+Pb

Step 3: Dividing the equation by RT

  • Dividing by RT in both LHS and RHS, we get,

pVRT=RTRT+pbRTSince,Z=pVRTpVRT=1+pbRT

​Hence, this is the correct option.

Explanation for incorrect option:

(B) 1-pbRT

  • This equation does not match the above equation of very high pressure. so this is an incorrect option.

(C) 1-bVRT

  • This equation does not match the above equation of very high pressure. so this is an incorrect option.

(D) pbRT

  • This equation does not match the above equation of very high pressure. so this is an incorrect option.

Hence, the correct option is (A) 1+pbRT


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