At what speed, the velocity head of water is equal to pressure head of 40 cm of mercury?

\(Velocity head = frac{1}{2}rho v^{2}\) \(p = rho gh\) from the problem we know that, h =40 cm of hg \(g=frac{10cm^{3}}{s^{2}}\) \(frac{1}{2}rho v^{2}=rho gh\) v=sqrt(2gh) v=282.8 cm/sec =10.32 m/s

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