Question

Both $xandy$ vary inversely with each other. When $xis10,yis6$, which of the following is not a possible pair of corresponding values of x $andy?$

• A. $12and5$
• B. $15and4$
• C. $25and2.4$
• D. $45and1.3$

Answer 1

The correct option is D

$45and1.3$

Given

• $x=10$
• $y=6$

since $xandy$ vary inversely, so

$xy=k$(constant)

Putting the value of $xandy$, we get;

$10\times 6=60$

Now if we observe the options available;

Option$\left(a\right)\Rightarrow 12and5\Rightarrow 12\times 5=60$

Option $\left(b\right)\Rightarrow 15and4\Rightarrow 15\times 4=60$

Option ($c)\Rightarrow 25and2.4\Rightarrow 25\times 2.4=60$

Option $\left(d\right)\Rightarrow 45and1.3\Rightarrow 45\times 1.3=58.3$

Therefore, $45and1.3$ is not a possible pair of corresponding values of$xandy.$