Calculate following in 5.6g of nitrogena) number of moles of N2b)number of molecules of N2c)number of atoms of nitrogen

Given that

5.6g of nitrogen

Atomic mass of nitrogen = 14u

We know that,

Molar atomic mass of nitrogen = 14g mol-1

Molar mass of N2 = 2 x 14g mol-1 = 28g mol-1

a) No.of moles of N2 in 5.6g of nitrogen

= 5.6g/28g mol-1

=0.2 mol

b) No.of molecules of N2 in 5.6g of nitrogen

= 6.023 x 1023 x no.of moles of N2

= 6.023 x 1023 x 0.2

= 1.2 x 1023

c) One molecule of N2 has two N atoms

No of atoms of nitrogen

= 2 x no.of N2 molecules

= 2 x 1.2 x 1023

= 2.4 x 1023

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