Question

The spin multiplicity of nitrogen in the ground state.

Answer 1

Multipilicity of an Element:

The energy level at 2S + 1 is called Multiplicity where S stands for Total spin angular momentum.

Calculation Spin Multiplicity for Nitrogen:-

For Nitrogen, Z = 7

So, its electronic configuration = $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^3$

Total Number of electrons in Nitrogen = 7

For the Neutral atom,

Number of Electrons = Number of Protons

So, Number of Protons = 7

Nitrogen has 3 unpaired electrons in its outermost shell.

So, S = Total spin = $\frac{1}{2}+\frac{1}{2}+\frac{1}{2}$

S = $\frac{3}{2}$

Now, spin multiplicity = 2S + 1 = 2 x $\frac{3}{2}$ + 1 = 4

Therefore, spin multiplicity of nitrogen = 4