1. Draw a line segment of base BC = 8 cm
2. Measure and draw ∠B = 45° and extend the ray BX
3. Using a compass and measure AB-AC = 3.5 cm.
4. Considering B as a centre and draw an arc at the point be D on the ray BX
5. Join DC
6. Now draw the perpendicular bisector of the line CD and the intersection point is assumed as A.
7. Join AC
8. Hence, ABC is the required triangle.